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www.jeremykun.com | ||
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nhigham.com
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| | | | | The Cayley-Hamilton Theorem says that a square matrix $LATEX A$ satisfies its characteristic equation, that is $latex p(A) = 0$ where $latex p(t) = \det(tI-A)$ is the characteristic polynomial. This statement is not simply the substitution ``$latex p(A) = \det(A - A) = 0$'', which is not valid since $latex t$ must remain a scalar... | |
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jiggerwit.wordpress.com
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| | | | | In the texbook I'm using for a first course in algebraic geometry, the proof of Bezout's theorem is awful. Looking around, I find an abundance of awful proofs. A good proof is one that I would want to commit to memory. Here is a good proof of Bezout's theorem, which is due to Gurjar and... | |
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alanrendall.wordpress.com
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| | | | | The theorem of the title is about dividing smooth functions by other smooth functions or, in other words, representing a given smooth function in terms of products of other smooth functions. A large part of the account which follows is based on that in the book 'Normal Forms and Unfoldings for Local Dynamical Systems' by... | |
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dismalsci.wordpress.com
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| | | As an experiment, I have recently started using Vim as my primary text editor. While I have been an Emacs aficionado for a very, very long time - clocking in at almost 16 years - Vim is something that I have always been curious about, and tinkered with from time to time, while ending up... | ||
