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| | | | | www.ethanepperly.com | |
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| | | | | nhigham.com | |
| | | | | The trace of an $latex n\times n$ matrix is the sum of its diagonal elements: $latex \mathrm{trace}(A) = \sum_{i=1}^n a_{ii}$. The trace is linear, that is, $latex \mathrm{trace}(A+B) = \mathrm{trace}(A) + \mathrm{trace}(B)$, and $latex \mathrm{trace}(A) = \mathrm{trace}(A^T)$. A key fact is that the trace is also the sum of the eigenvalues. The proof is by... | |
| | | | | mattbaker.blog | |
| | | | | Test your intuition: is the following true or false? Assertion 1: If $latex A$ is a square matrix over a commutative ring $latex R$, the rows of $latex A$ are linearly independent over $latex R$ if and only if the columns of $latex A$ are linearly independent over $latex R$. (All rings in this post... | |
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