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mathematicaloddsandends.wordpress.com
| | fabricebaudoin.blog
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| | In this section, we consider a diffusion operator $latex L=\sum_{i,j=1}^n \sigma_{ij} (x) \frac{\partial^2}{ \partial x_i \partial x_j} +\sum_{i=1}^n b_i (x)\frac{\partial}{\partial x_i}, $ where $latex b_i$ and $latex \sigma_{ij}$ are continuous functions on $latex \mathbb{R}^n$ and for every $latex x \in \mathbb{R}^n$, the matrix $latex (\sigma_{ij}(x))_{1\le i,j\le n}$ is a symmetric and non negative matrix. Our...
| | statisticaloddsandends.wordpress.com
3.6 parsecs away

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| | I just came across a really interesting and simple algorithm for estimating the number of distinct elements in a stream of data. The paper (Chakraborty et al. 2023) is available on arXiv; see this Quanta article (Reference 2) for a layman's explanation. Problem statement Let's state the problem formally. Let's say we are given a...
| | mkatkov.wordpress.com
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| | For probability space $latex (\Omega, \mathcal{F}, \mathbb{P})$ with $latex A \in \mathcal{F}$ the indicator random variable $latex {\bf 1}_A : \Omega \rightarrow \mathbb{R} = \left\{ \begin{array}{cc} 1, & \omega \in A \\ 0, & \omega \notin A \end{array} \right.$ Than expected value of the indicator variable is the probability of the event $latex \omega \in...
| | rapuran.wordpress.com
8.2 parsecs away

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