/explore

Click through on any links that interest you or select the planets on the right to continue exploring the Outer Web.
You are here

nhigham.com
| | stephenmalina.com
2.2 parsecs away

Travel
| | Matrix Potpourri # As part of reviewing Linear Algebra for my Machine Learning class, I've noticed there's a bunch of matrix terminology that I didn't encounter during my proof-based self-study of LA from Linear Algebra Done Right. This post is mostly intended to consolidate my own understanding and to act as a reference to future me, but if it also helps others in a similar position, that's even better!
| | tiao.io
2.0 parsecs away

Travel
| | Suppose we're given a positive semidefinite (PSD) matrix $\mathbf{A} \in \mathbb{R}^{N \times N}$ to which we wish to update by some low-rank matrix $\mathbf{U} \mathbf{U}^\top \in \mathbb{R}^{N \times N}$, $$\mathbf{B} \triangleq \mathbf{A} + \mathbf{U} \mathbf{U}^\top,$$ where the update factor matrix $\mathbf{U} \in \mathbb{R}^{N \times M}$. To be more precise, the low-rank update is rank-$M$ for some $M \ll N$. What is the best way to calculate the Cholesky decomposition of $\mathbf{B}$? Given ......
| | hadrienj.github.io
1.6 parsecs away

Travel
| | This post will introduce you to special kind of matrices: the identity matrix and the inverse matrix. We will use Python/Numpy as a tool to get a better intu...
| | statisticaloddsandends.wordpress.com
21.8 parsecs away

Travel
| If $latex Z_1, \dots, Z_n$ are independent $latex \text{Cauchy}(0, 1)$ variables and $latex w= (w_1, \dots, w_n)$ is a random vector independent of the $latex Z_i$'s with $latex w_i \geq 0$ for all $latex i$ and $latex w_1 + \dots w_n = 0$, it is well-known that $latex \displaystyle\sum_{i=1}^n w_i Z_i$ also has a $latex...