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almostsuremath.com
| | xorshammer.com
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| | Here's a puzzle: You and Bob are going to play a game which has the following steps. Bob thinks of some function $latex f\colon \mathbb{R}\to\mathbb{R}$ (it's arbitrary: it doesn't have to be continuous or anything). You pick an $latex x \in \mathbb{R}$. Bob reveals to you the table of values $latex \{(x_0, f(x_0))\mid x_0\ne x\}$...
| | gregorygundersen.com
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| | jmanton.wordpress.com
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| | If $latex Y$ is a $latex \sigma(X)$-measurable random variable then there exists a Borel-measurable function $latex f \colon \mathbb{R} \rightarrow \mathbb{R}$ such that $latex Y = f(X)$. The standard proof of this fact leaves several questions unanswered. This note explains what goes wrong when attempting a "direct" proof. It also explains how the standard proof...
| | willssunnysideblog.wordpress.com
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| via Bar jokes for English majors