/explore
|
You are here |
francisbach.com | ||
| | | | |
nickhar.wordpress.com
1. Low-rank approximation of matrices Let $latex {A}&fg=000000$ be an arbitrary $latex {n \times m}&fg=000000$ matrix. We assume $latex {n \leq m}&fg=000000$. We consider the problem of approximating $latex {A}&fg=000000$ by a low-rank matrix. For example, we could seek to find a rank $latex {s}&fg=000000$ matrix $latex {B}&fg=000000$ minimizing $latex { \lVert A - B... |
|
| | | | | ||
| | | | |
www.ethanepperly.com
[AI summary] The user has provided a comprehensive set of mathematical derivations and inequalities related to probability and statistics, focusing on bounding the probability that the sample mean deviates from its expected value. The key points include: (1) Using the Chernoff bound to derive a tail inequality for bounded random variables, (2) Applying the Hoeffding's inequality to show that the probability of the sample mean deviating by more than t is exponentially small in n, (3) Deriving the final result that the probability is bounded by 2exp(-2nt^2/(b-a)^2), and (4) Mentioning the connection to the Hoeffding inequality. The user also included some unrelated text about an ORCID iD and an email profile, which seems to be an error or unrelated information... |
|
| | | | | ||
| | | | |
nhigham.com
A real $latex n\times n$ matrix $LATEX A$ is symmetric positive definite if it is symmetric ($LATEX A$ is equal to its transpose, $LATEX A^T$) and $latex x^T\!Ax > 0 \quad \mbox{for all nonzero vectors}~x. $ By making particular choices of $latex x$ in this definition we can derive the inequalities $latex \begin{alignedat}{2} a_{ii} &>0... |
|
| | | | | ||
| | | | |
zserge.com
Neural network and deep learning introduction for those who skipped the math class but wants to follow the trend |
|
| | | |||