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\|	\|	??????? ?????? ?? ??????? ??????????? 465 ??????! SELECT A.ID, A.LOGIN, A.NAME, A.LASTNAME, A.EMAIL FROM ACCOUNT A WHERE (A.LOGIN LIKE '%%') AND (A.NAME LIKE '%????????%' OR A.LASTNAME LIKE '%????????%') AND A.COMPANY_ID = 1 ORDER BY A.LOGIN ??? ???????, ????????? ???? ?? ??????? A.COMPANY_ID = 1 ???????? ??????? ???????????????? SQL> SELECT 'ALL' as "Condition", count(*) FROM ACCOUNT...	6.0 parsecs away Travel
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