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xorshammer.com
| | mikespivey.wordpress.com
10.8 parsecs away

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| | It's fairly well-known, to those who know it, that $latex \displaystyle \left(\sum_{k=1}^n k \right)^2 = \frac{n^2(n+1)^2}{4} = \sum_{k=1}^n k^3 $. In other words, the square of the sum of the first n positive integers equals the sum of the cubes of the first n positive integers. It's probably less well-known that a similar relationship holds...
| | mkatkov.wordpress.com
11.8 parsecs away

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| | For probability space $latex (\Omega, \mathcal{F}, \mathbb{P})$ with $latex A \in \mathcal{F}$ the indicator random variable $latex {\bf 1}_A : \Omega \rightarrow \mathbb{R} = \left\{ \begin{array}{cc} 1, & \omega \in A \\ 0, & \omega \notin A \end{array} \right.$ Than expected value of the indicator variable is the probability of the event $latex \omega \in...
| | matheuscmss.wordpress.com
13.5 parsecs away

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| | In 1966, M. Kac wrote a famous article asking whetherCan one hear the shape of drum?: mathematically speaking, one wants to reconstruct (up to isometries) a domain from the knowledge of the spectrum of its Laplacian. In his article, M. Kac showed that one can hear the shape of a disk $latex {\mathbb{D}(0,R)=\{z\in\mathbb{R}^2:|z|\leq R\}}&fg=000000$ because...
| | fredrikj.net
83.4 parsecs away

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