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principlesofcryptography.com | ||
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www.themathdoctors.org
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mikespivey.wordpress.com
It's fairly well-known, to those who know it, that $latex \displaystyle \left(\sum_{k=1}^n k \right)^2 = \frac{n^2(n+1)^2}{4} = \sum_{k=1}^n k^3 $. In other words, the square of the sum of the first n positive integers equals the sum of the cubes of the first n positive integers. It's probably less well-known that a similar relationship holds... |
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relatedwork.blogspot.com
WARNING: the following contains a whole lot of pedantry about proving theorems at a level of detail such that you could likely convince a co... |
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thirtybythirty.org
Join me as I try to meet the challenge of travelling to 30 countries before my 30th birthday |
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